-6(u+2)=2u-4+2(5u+4)

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Solution for -6(u+2)=2u-4+2(5u+4) equation: 



-6(u+2)=2u-4+2(5u+4)

We move all terms to the left:

-6(u+2)-(2u-4+2(5u+4))=0

We multiply parentheses

-6u-(2u-4+2(5u+4))-12=0



We calculate terms in parentheses: -(2u-4+2(5u+4)), so:

2u-4+2(5u+4)

determiningTheFunctionDomain
2u+2(5u+4)-4

We multiply parentheses

2u+10u+8-4

We add all the numbers together, and all the variables

12u+4

Back to the equation:

-(12u+4)



We get rid of parentheses

-6u-12u-4-12=0

We add all the numbers together, and all the variables

-18u-16=0

We move all terms containing u to the left, all other terms to the right

-18u=16

u=16/-18

u=-8/9

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