4(v-1)=4v+2-4(-2v-1)

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Solution for 4(v-1)=4v+2-4(-2v-1) equation: 



4(v-1)=4v+2-4(-2v-1)

We move all terms to the left:

4(v-1)-(4v+2-4(-2v-1))=0

We multiply parentheses

4v-(4v+2-4(-2v-1))-4=0



We calculate terms in parentheses: -(4v+2-4(-2v-1)), so:

4v+2-4(-2v-1)

determiningTheFunctionDomain
4v-4(-2v-1)+2

We multiply parentheses

4v+8v+4+2

We add all the numbers together, and all the variables

12v+6

Back to the equation:

-(12v+6)



We get rid of parentheses

4v-12v-6-4=0

We add all the numbers together, and all the variables

-8v-10=0

We move all terms containing v to the left, all other terms to the right

-8v=10

v=10/-8

v=-1+1/4

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