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x-10/x=99/x+10
We move all terms to the left:
x-10/x-(99/x+10)=0
Domain of the equation: x!=0
x∈R
Domain of the equation: x+10)!=0We get rid of parentheses
x∈R
x-10/x-99/x-10=0
We multiply all the terms by the denominator
x*x-10*x-10-99=0
We add all the numbers together, and all the variables
-10x+x*x-109=0
Wy multiply elements
x^2-10x-109=0
a = 1; b = -10; c = -109;
Δ = b2-4ac
Δ = -102-4·1·(-109)
Δ = 536
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{536}=\sqrt{4*134}=\sqrt{4}*\sqrt{134}=2\sqrt{134}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-10)-2\sqrt{134}}{2*1}=\frac{10-2\sqrt{134}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-10)+2\sqrt{134}}{2*1}=\frac{10+2\sqrt{134}}{2} $
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