3(x+2)+12=9-(x-6)

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Solution for 3(x+2)+12=9-(x-6) equation: 



3(x+2)+12=9-(x-6)

We move all terms to the left:

3(x+2)+12-(9-(x-6))=0

We multiply parentheses

3x-(9-(x-6))+6+12=0



We calculate terms in parentheses: -(9-(x-6)), so:

9-(x-6)

determiningTheFunctionDomain
-(x-6)+9

We get rid of parentheses

-x+6+9

We add all the numbers together, and all the variables

-1x+15

Back to the equation:

-(-1x+15)



We add all the numbers together, and all the variables

3x-(-1x+15)+18=0

We get rid of parentheses

3x+1x-15+18=0

We add all the numbers together, and all the variables

4x+3=0

We move all terms containing x to the left, all other terms to the right

4x=-3

x=-3/4

x=-3/4

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