8x=4-2(1-x)=6+10x-8

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Solution for 8x=4-2(1-x)=6+10x-8 equation: 



8x=4-2(1-x)=6+10x-8

We move all terms to the left:

8x-(4-2(1-x))=0

We add all the numbers together, and all the variables

8x-(4-2(-1x+1))=0



We calculate terms in parentheses: -(4-2(-1x+1)), so:

4-2(-1x+1)

determiningTheFunctionDomain
-2(-1x+1)+4

We multiply parentheses

2x-2+4

We add all the numbers together, and all the variables

2x+2

Back to the equation:

-(2x+2)



We get rid of parentheses

8x-2x-2=0

We add all the numbers together, and all the variables

6x-2=0

We move all terms containing x to the left, all other terms to the right

6x=2

x=2/6

x=1/3

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