5.8/3y+6=3.8y+4.32

Solution for 5.8/3y+6=3.8y+4.32 equation:

5.8/3y+6=3.8y+4.32

We move all terms to the left:

5.8/3y+6-(3.8y+4.32)=0


Domain of the equation: 3y!=0

y!=0/3

y!=0

y∈R


We get rid of parentheses

5.8/3y-3.8y-4.32+6=0

We multiply all the terms by the denominator


-(3.8y)*3y-(4.32)*3y+6*3y+5.8=0

We add all the numbers together, and all the variables

-(+3.8y)*3y-(4.32)*3y+6*3y+5.8=0

We multiply parentheses

-9y^2-12.96y+6*3y+5.8=0

Wy multiply elements

-9y^2-12.96y+18y+5.8=0

We add all the numbers together, and all the variables

-9y^2+5.04y+5.8=0

a = -9; b = 5.04; c = +5.8;
Δ = b2-4ac
Δ = 5.042-4·(-9)·5.8
Δ = 234.2016
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5.04)-\sqrt{234.2016}}{2*-9}=\frac{-5.04-\sqrt{234.2016}}{-18}
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5.04)+\sqrt{234.2016}}{2*-9}=\frac{-5.04+\sqrt{234.2016}}{-18}
$