x+2)/3-(4x+5)/6=x+1

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Solution for x+2)/3-(4x+5)/6=x+1 equation: 



x+2)/3-(4x+5)/6=x+1

We move all terms to the left:

x+2)/3-(4x+5)/6-(x+1)=0



Domain of the equation: 3-(4x!=0

We move all terms containing x to the left, all other terms to the right

-(4x!=-3

x∈R





Domain of the equation: 6-(x!=0

We move all terms containing x to the left, all other terms to the right

-(x!=-6

x∈R



We add all the numbers together, and all the variables

x+2)/3-(4x+5)/6-(x=0

We calculate fractions


x-x/(-(4x*6-(x+3)+5*3-4x/(-(4x*6-(x+3)+2*6=0

We can not solve this equation

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