2x-41=2(5x+2)-5

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Solution for 2x-41=2(5x+2)-5 equation: 



2x-41=2(5x+2)-5

We move all terms to the left:

2x-41-(2(5x+2)-5)=0



We calculate terms in parentheses: -(2(5x+2)-5), so:

2(5x+2)-5

We multiply parentheses

10x+4-5

We add all the numbers together, and all the variables

10x-1

Back to the equation:

-(10x-1)



We get rid of parentheses

2x-10x+1-41=0

We add all the numbers together, and all the variables

-8x-40=0

We move all terms containing x to the left, all other terms to the right

-8x=40

x=40/-8

x=-5

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