(2x+1)(4x-2)=-10

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Solution for (2x+1)(4x-2)=-10 equation: 



(2x+1)(4x-2)=-10

We move all terms to the left:

(2x+1)(4x-2)-(-10)=0

We add all the numbers together, and all the variables

(2x+1)(4x-2)+10=0

We multiply parentheses ..

(+8x^2-4x+4x-2)+10=0

We get rid of parentheses

8x^2-4x+4x-2+10=0

We add all the numbers together, and all the variables

8x^2+8=0

a = 8; b = 0; c = +8;
Δ = b2-4ac
Δ = 02-4·8·8
Δ = -256
Delta is less than zero, so there is no solution for the equation

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