(x-2)(2x+3)=2x(x+8)

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Solution for (x-2)(2x+3)=2x(x+8) equation: 



(x-2)(2x+3)=2x(x+8)

We move all terms to the left:

(x-2)(2x+3)-(2x(x+8))=0

We multiply parentheses ..

(+2x^2+3x-4x-6)-(2x(x+8))=0



We calculate terms in parentheses: -(2x(x+8)), so:

2x(x+8)

We multiply parentheses

2x^2+16x

Back to the equation:

-(2x^2+16x)



We get rid of parentheses

2x^2-2x^2+3x-4x-16x-6=0

We add all the numbers together, and all the variables

-17x-6=0

We move all terms containing x to the left, all other terms to the right

-17x=6

x=6/-17

x=-6/17

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