5(4k-7)=6(k-2)

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Solution for 5(4k-7)=6(k-2) equation: 



5(4k-7)=6(k-2)

We move all terms to the left:

5(4k-7)-(6(k-2))=0

We multiply parentheses

20k-(6(k-2))-35=0



We calculate terms in parentheses: -(6(k-2)), so:

6(k-2)

We multiply parentheses

6k-12

Back to the equation:

-(6k-12)



We get rid of parentheses

20k-6k+12-35=0

We add all the numbers together, and all the variables

14k-23=0

We move all terms containing k to the left, all other terms to the right

14k=23

k=23/14

k=1+9/14

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