n2-n-182=0

Solution for n2-n-182=0 equation:

n2-n-182=0

We add all the numbers together, and all the variables

n^2-1n-182=0

a = 1; b = -1; c = -182;
Δ = b2-4ac
Δ = -12-4·1·(-182)
Δ = 729
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{729}=27$
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-27}{2*1}=\frac{-26}{2}
=-13
$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+27}{2*1}=\frac{28}{2}
=14
$