((3x+26)/5)+((x+45)/6)=15

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Solution for ((3x+26)/5)+((x+45)/6)=15 equation:



((3x+26)/5)+((x+45)/6)=15
We move all terms to the left:
((3x+26)/5)+((x+45)/6)-(15)=0
We calculate fractions
(18x+156)/()+(5x+225)/()-15=0
We multiply all the terms by the denominator
(18x+156)+(5x+225)-15*()=0
We add all the numbers together, and all the variables
(18x+156)+(5x+225)=0
We get rid of parentheses
18x+5x+156+225=0
We add all the numbers together, and all the variables
23x+381=0
We move all terms containing x to the left, all other terms to the right
23x=-381
x=-381/23
x=-16+13/23

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