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20/x+6=36/2x-6
We move all terms to the left:
20/x+6-(36/2x-6)=0
Domain of the equation: x!=0
x∈R
Domain of the equation: 2x-6)!=0We get rid of parentheses
x∈R
20/x-36/2x+6+6=0
We calculate fractions
40x/2x^2+(-36x)/2x^2+6+6=0
We add all the numbers together, and all the variables
40x/2x^2+(-36x)/2x^2+12=0
We multiply all the terms by the denominator
40x+(-36x)+12*2x^2=0
Wy multiply elements
24x^2+40x+(-36x)=0
We get rid of parentheses
24x^2+40x-36x=0
We add all the numbers together, and all the variables
24x^2+4x=0
a = 24; b = 4; c = 0;
Δ = b2-4ac
Δ = 42-4·24·0
Δ = 16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{16}=4$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-4}{2*24}=\frac{-8}{48} =-1/6 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+4}{2*24}=\frac{0}{48} =0 $
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