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5(x+3)(x+3)=0
We multiply parentheses ..
5(+x^2+3x+3x+9)=0
We multiply parentheses
5x^2+15x+15x+45=0
We add all the numbers together, and all the variables
5x^2+30x+45=0
a = 5; b = 30; c = +45;
Δ = b2-4ac
Δ = 302-4·5·45
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$x=\frac{-b}{2a}=\frac{-30}{10}=-3$
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