7(2y-1)+3y=3(2-y)+9

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Solution for 7(2y-1)+3y=3(2-y)+9 equation: 



7(2y-1)+3y=3(2-y)+9

We move all terms to the left:

7(2y-1)+3y-(3(2-y)+9)=0

We add all the numbers together, and all the variables

7(2y-1)+3y-(3(-1y+2)+9)=0

We add all the numbers together, and all the variables

3y+7(2y-1)-(3(-1y+2)+9)=0

We multiply parentheses

3y+14y-(3(-1y+2)+9)-7=0



We calculate terms in parentheses: -(3(-1y+2)+9), so:

3(-1y+2)+9

We multiply parentheses

-3y+6+9

We add all the numbers together, and all the variables

-3y+15

Back to the equation:

-(-3y+15)



We add all the numbers together, and all the variables

17y-(-3y+15)-7=0

We get rid of parentheses

17y+3y-15-7=0

We add all the numbers together, and all the variables

20y-22=0

We move all terms containing y to the left, all other terms to the right

20y=22

y=22/20

y=1+1/10

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