n2+36n=0

Solution for n2+36n=0 equation:

n2+36n=0

We add all the numbers together, and all the variables

n^2+36n=0

a = 1; b = 36; c = 0;
Δ = b2-4ac
Δ = 362-4·1·0
Δ = 1296
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1296}=36$
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(36)-36}{2*1}=\frac{-72}{2}
=-36
$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(36)+36}{2*1}=\frac{0}{2}
=0
$