3(2k+3)=6-(3k-5)

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Solution for 3(2k+3)=6-(3k-5) equation: 



3(2k+3)=6-(3k-5)

We move all terms to the left:

3(2k+3)-(6-(3k-5))=0

We multiply parentheses

6k-(6-(3k-5))+9=0



We calculate terms in parentheses: -(6-(3k-5)), so:

6-(3k-5)

determiningTheFunctionDomain
-(3k-5)+6

We get rid of parentheses

-3k+5+6

We add all the numbers together, and all the variables

-3k+11

Back to the equation:

-(-3k+11)



We get rid of parentheses

6k+3k-11+9=0

We add all the numbers together, and all the variables

9k-2=0

We move all terms containing k to the left, all other terms to the right

9k=2

k=2/9

k=2/9

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