2(x+3)+18+4(10x-9)=42

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Solution for 2(x+3)+18+4(10x-9)=42 equation: 



2(x+3)+18+4(10x-9)=42

We move all terms to the left:

2(x+3)+18+4(10x-9)-(42)=0

We add all the numbers together, and all the variables

2(x+3)+4(10x-9)-24=0

We multiply parentheses

2x+40x+6-36-24=0

We add all the numbers together, and all the variables

42x-54=0

We move all terms containing x to the left, all other terms to the right

42x=54

x=54/42

x=1+2/7

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