7(b-3)+6=2(2b+1)+7

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Solution for 7(b-3)+6=2(2b+1)+7 equation: 



7(b-3)+6=2(2b+1)+7

We move all terms to the left:

7(b-3)+6-(2(2b+1)+7)=0

We multiply parentheses

7b-(2(2b+1)+7)-21+6=0



We calculate terms in parentheses: -(2(2b+1)+7), so:

2(2b+1)+7

We multiply parentheses

4b+2+7

We add all the numbers together, and all the variables

4b+9

Back to the equation:

-(4b+9)



We add all the numbers together, and all the variables

7b-(4b+9)-15=0

We get rid of parentheses

7b-4b-9-15=0

We add all the numbers together, and all the variables

3b-24=0

We move all terms containing b to the left, all other terms to the right

3b=24

b=24/3

b=8

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