h2+7h-1=0

Solution for h2+7h-1=0 equation:

h2+7h-1=0

We add all the numbers together, and all the variables

h^2+7h-1=0

a = 1; b = 7; c = -1;
Δ = b2-4ac
Δ = 72-4·1·(-1)
Δ = 53
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-\sqrt{53}}{2*1}=\frac{-7-\sqrt{53}}{2}
$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+\sqrt{53}}{2*1}=\frac{-7+\sqrt{53}}{2}
$