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x(x-3)3x=(x+2)3+1
We move all terms to the left:
x(x-3)3x-((x+2)3+1)=0
We multiply parentheses
3x^3-9x^2-((x+2)3+1)=0
We calculate terms in parentheses: -((x+2)3+1), so:We do not support expression: x^3
(x+2)3+1
We multiply parentheses
3x+6+1
We add all the numbers together, and all the variables
3x+7
Back to the equation:
-(3x+7)
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