12-3*(x+2)=(x+2)*(1-3x)

Solution for 12-3*(x+2)=(x+2)*(1-3x) equation:

12-3(x+2)=(x+2)(1-3x)

We move all terms to the left:

12-3(x+2)-((x+2)(1-3x))=0

We add all the numbers together, and all the variables

-3(x+2)-((x+2)(-3x+1))+12=0

We multiply parentheses

-3x-((x+2)(-3x+1))-6+12=0

We multiply parentheses ..

-((-3x^2+x-6x+2))-3x-6+12=0


We calculate terms in parentheses: -((-3x^2+x-6x+2)), so:

(-3x^2+x-6x+2)

We get rid of parentheses

-3x^2+x-6x+2

We add all the numbers together, and all the variables

-3x^2-5x+2

Back to the equation:

-(-3x^2-5x+2)


We add all the numbers together, and all the variables

-(-3x^2-5x+2)-3x+6=0

We get rid of parentheses

3x^2+5x-3x-2+6=0

We add all the numbers together, and all the variables

3x^2+2x+4=0

a = 3; b = 2; c = +4;
Δ = b2-4ac
Δ = 22-4·3·4
Δ = -44
Delta is less than zero, so there is no solution for the equation