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a2+18a-66=-3
We move all terms to the left:
a2+18a-66-(-3)=0
We add all the numbers together, and all the variables
a^2+18a-63=0
a = 1; b = 18; c = -63;
Δ = b2-4ac
Δ = 182-4·1·(-63)
Δ = 576
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{576}=24$$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(18)-24}{2*1}=\frac{-42}{2} =-21 $$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(18)+24}{2*1}=\frac{6}{2} =3 $
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