7x2+140=63x

Solution for 7x2+140=63x equation:

7x^2+140=63x

We move all terms to the left:

7x^2+140-(63x)=0

a = 7; b = -63; c = +140;
Δ = b2-4ac
Δ = -632-4·7·140
Δ = 49
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{49}=7$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-63)-7}{2*7}=\frac{56}{14}
=4
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-63)+7}{2*7}=\frac{70}{14}
=5
$