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81k^2-3=1
We move all terms to the left:
81k^2-3-(1)=0
We add all the numbers together, and all the variables
81k^2-4=0
a = 81; b = 0; c = -4;
Δ = b2-4ac
Δ = 02-4·81·(-4)
Δ = 1296
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1296}=36$$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-36}{2*81}=\frac{-36}{162} =-2/9 $$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+36}{2*81}=\frac{36}{162} =2/9 $
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