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X=14/X+3
We move all terms to the left:
X-(14/X+3)=0
Domain of the equation: X+3)!=0We get rid of parentheses
X∈R
X-14/X-3=0
We multiply all the terms by the denominator
X*X-3*X-14=0
We add all the numbers together, and all the variables
-3X+X*X-14=0
Wy multiply elements
X^2-3X-14=0
a = 1; b = -3; c = -14;
Δ = b2-4ac
Δ = -32-4·1·(-14)
Δ = 65
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-\sqrt{65}}{2*1}=\frac{3-\sqrt{65}}{2} $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+\sqrt{65}}{2*1}=\frac{3+\sqrt{65}}{2} $
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