x(3x-3)=(3x+9)(x-8)

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Solution for x(3x-3)=(3x+9)(x-8) equation: 



x(3x-3)=(3x+9)(x-8)

We move all terms to the left:

x(3x-3)-((3x+9)(x-8))=0

We multiply parentheses

3x^2-3x-((3x+9)(x-8))=0

We multiply parentheses ..

3x^2-((+3x^2-24x+9x-72))-3x=0



We calculate terms in parentheses: -((+3x^2-24x+9x-72)), so:

(+3x^2-24x+9x-72)

We get rid of parentheses

3x^2-24x+9x-72

We add all the numbers together, and all the variables

3x^2-15x-72

Back to the equation:

-(3x^2-15x-72)



We add all the numbers together, and all the variables

3x^2-3x-(3x^2-15x-72)=0

We get rid of parentheses

3x^2-3x^2-3x+15x+72=0

We add all the numbers together, and all the variables

12x+72=0

We move all terms containing x to the left, all other terms to the right

12x=-72

x=-72/12

x=-6

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