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X2-4X-9=29
We move all terms to the left:
X2-4X-9-(29)=0
We add all the numbers together, and all the variables
X^2-4X-38=0
a = 1; b = -4; c = -38;
Δ = b2-4ac
Δ = -42-4·1·(-38)
Δ = 168
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{168}=\sqrt{4*42}=\sqrt{4}*\sqrt{42}=2\sqrt{42}$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-4)-2\sqrt{42}}{2*1}=\frac{4-2\sqrt{42}}{2} $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-4)+2\sqrt{42}}{2*1}=\frac{4+2\sqrt{42}}{2} $
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