30+(6x)=40+(2x+(8x))

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Solution for 30+(6x)=40+(2x+(8x)) equation: 



30+(6x)=40+(2x+(8x))

We move all terms to the left:

30+(6x)-(40+(2x+(8x)))=0

We add all the numbers together, and all the variables

6x-(40+(+10x))+30=0



We calculate terms in parentheses: -(40+(+10x)), so:

40+(+10x)

determiningTheFunctionDomain
(+10x)+40

We get rid of parentheses

10x+40

Back to the equation:

-(10x+40)



We get rid of parentheses

6x-10x-40+30=0

We add all the numbers together, and all the variables

-4x-10=0

We move all terms containing x to the left, all other terms to the right

-4x=10

x=10/-4

x=-2+1/2

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