10+x=5(1/50x+2)

Solution for 10+x=5(1/50x+2) equation:

10+x=5(1/50x+2)

We move all terms to the left:

10+x-(5(1/50x+2))=0


Domain of the equation: 50x+2))!=0

x∈R


We multiply all the terms by the denominator


x*50x+10*50x+2))-(5(1+2))=0

We add all the numbers together, and all the variables

x*50x+10*50x+2))-(53)=0

We add all the numbers together, and all the variables

x*50x+10*50x=0

Wy multiply elements

50x^2+500x=0

a = 50; b = 500; c = 0;
Δ = b2-4ac
Δ = 5002-4·50·0
Δ = 250000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{250000}=500$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(500)-500}{2*50}=\frac{-1000}{100}
=-10
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(500)+500}{2*50}=\frac{0}{100}
=0
$