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3(x-5)=2(4-3x)
We move all terms to the left:
3(x-5)-(2(4-3x))=0
We add all the numbers together, and all the variables
3(x-5)-(2(-3x+4))=0
We multiply parentheses
3x-(2(-3x+4))-15=0
We calculate terms in parentheses: -(2(-3x+4)), so:We get rid of parentheses
2(-3x+4)
We multiply parentheses
-6x+8
Back to the equation:
-(-6x+8)
3x+6x-8-15=0
We add all the numbers together, and all the variables
9x-23=0
We move all terms containing x to the left, all other terms to the right
9x=23
x=23/9
x=2+5/9
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