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X2+9X-10=8X-6
We move all terms to the left:
X2+9X-10-(8X-6)=0
We add all the numbers together, and all the variables
X^2+9X-(8X-6)-10=0
We get rid of parentheses
X^2+9X-8X+6-10=0
We add all the numbers together, and all the variables
X^2+X-4=0
a = 1; b = 1; c = -4;
Δ = b2-4ac
Δ = 12-4·1·(-4)
Δ = 17
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{17}}{2*1}=\frac{-1-\sqrt{17}}{2} $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{17}}{2*1}=\frac{-1+\sqrt{17}}{2} $
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