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X2+55X-300=0
We add all the numbers together, and all the variables
X^2+55X-300=0
a = 1; b = 55; c = -300;
Δ = b2-4ac
Δ = 552-4·1·(-300)
Δ = 4225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{4225}=65$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(55)-65}{2*1}=\frac{-120}{2} =-60 $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(55)+65}{2*1}=\frac{10}{2} =5 $
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