-4(y-4y)+3=-3(2y-y)+4+14y

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Solution for -4(y-4y)+3=-3(2y-y)+4+14y equation: 



-4(y-4y)+3=-3(2y-y)+4+14y

We move all terms to the left:

-4(y-4y)+3-(-3(2y-y)+4+14y)=0

We add all the numbers together, and all the variables

-4(-3y)-(-3(+y)+4+14y)+3=0

We multiply parentheses

12y-(-3(+y)+4+14y)+3=0



We calculate terms in parentheses: -(-3(+y)+4+14y), so:

-3(+y)+4+14y

determiningTheFunctionDomain
-3(+y)+14y+4

We add all the numbers together, and all the variables

14y-3(+y)+4

We multiply parentheses

14y-3y+4

We add all the numbers together, and all the variables

11y+4

Back to the equation:

-(11y+4)



We get rid of parentheses

12y-11y-4+3=0

We add all the numbers together, and all the variables

y-1=0

We move all terms containing y to the left, all other terms to the right

y=1

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