x=12(10-2x)=4(2x+2)2(10-2(1))=4(2(1)+2)2(10-2)=4(2+2)

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Solution for x=12(10-2x)=4(2x+2)2(10-2(1))=4(2(1)+2)2(10-2)=4(2+2) equation: 



x=12(10-2x)=4(2x+2)2(10-2(1))=4(2(1)+2)2(10-2)=4(2+2)

We move all terms to the left:

x-(12(10-2x))=0

We add all the numbers together, and all the variables

x-(12(-2x+10))=0



We calculate terms in parentheses: -(12(-2x+10)), so:

12(-2x+10)

We multiply parentheses

-24x+120

Back to the equation:

-(-24x+120)



We get rid of parentheses

x+24x-120=0

We add all the numbers together, and all the variables

25x-120=0

We move all terms containing x to the left, all other terms to the right

25x=120

x=120/25

x=4+4/5

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