X2+4x-1242=0

Solution for X2+4x-1242=0 equation:

X2+4X-1242=0

We add all the numbers together, and all the variables

X^2+4X-1242=0

a = 1; b = 4; c = -1242;
Δ = b2-4ac
Δ = 42-4·1·(-1242)
Δ = 4984
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{4984}=\sqrt{4*1246}=\sqrt{4}*\sqrt{1246}=2\sqrt{1246}$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-2\sqrt{1246}}{2*1}=\frac{-4-2\sqrt{1246}}{2}
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+2\sqrt{1246}}{2*1}=\frac{-4+2\sqrt{1246}}{2}
$