2(2x+3)=(3x-1)+5

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Solution for 2(2x+3)=(3x-1)+5 equation: 



2(2x+3)=(3x-1)+5

We move all terms to the left:

2(2x+3)-((3x-1)+5)=0

We multiply parentheses

4x-((3x-1)+5)+6=0



We calculate terms in parentheses: -((3x-1)+5), so:

(3x-1)+5

We get rid of parentheses

3x-1+5

We add all the numbers together, and all the variables

3x+4

Back to the equation:

-(3x+4)



We get rid of parentheses

4x-3x-4+6=0

We add all the numbers together, and all the variables

x+2=0

We move all terms containing x to the left, all other terms to the right

x=-2

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