20X*2x=1

Solution for 20X*2x=1 equation:

20X*2X=1

We move all terms to the left:

20X*2X-(1)=0

Wy multiply elements

40X^2-1=0

a = 40; b = 0; c = -1;
Δ = b2-4ac
Δ = 02-4·40·(-1)
Δ = 160
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{160}=\sqrt{16*10}=\sqrt{16}*\sqrt{10}=4\sqrt{10}$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-4\sqrt{10}}{2*40}=\frac{0-4\sqrt{10}}{80}
=-\frac{4\sqrt{10}}{80}
=-\frac{\sqrt{10}}{20}
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+4\sqrt{10}}{2*40}=\frac{0+4\sqrt{10}}{80}
=\frac{4\sqrt{10}}{80}
=\frac{\sqrt{10}}{20}
$