(4y+1)/3+(2y-1)/2-(3y-7)/5=6

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Solution for (4y+1)/3+(2y-1)/2-(3y-7)/5=6 equation: 



(4y+1)/3+(2y-1)/2-(3y-7)/5=6

We move all terms to the left:

(4y+1)/3+(2y-1)/2-(3y-7)/5-(6)=0

We calculate fractions

There is no solution for this equation

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