X2+10x=171

Solution for X2+10x=171 equation:

X2+10X=171

We move all terms to the left:

X2+10X-(171)=0

We add all the numbers together, and all the variables

X^2+10X-171=0

a = 1; b = 10; c = -171;
Δ = b2-4ac
Δ = 102-4·1·(-171)
Δ = 784
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{784}=28$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10)-28}{2*1}=\frac{-38}{2}
=-19
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10)+28}{2*1}=\frac{18}{2}
=9
$