(x-3)+(3x-5)+(4x+3)/2(2x+2)+2(4x-1/2)=5/9

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Solution for (x-3)+(3x-5)+(4x+3)/2(2x+2)+2(4x-1/2)=5/9 equation: 



(x-3)+(3x-5)+(4x+3)/2(2x+2)+2(4x-1/2)=5/9

We move all terms to the left:

(x-3)+(3x-5)+(4x+3)/2(2x+2)+2(4x-1/2)-(5/9)=0



Domain of the equation: 2(2x+2)!=0

x∈R



We add all the numbers together, and all the variables

(x-3)+(3x-5)+(4x+3)/2(2x+2)+2(+4x-1/2)-(+5/9)=0

We multiply parentheses

(x-3)+(3x-5)+(4x+3)/2(2x+2)+8x-1/2*2-(+5/9)=0

We get rid of parentheses

x+3x+(4x+3)/2(2x+2)+8x-3-5-1/2*2-5/9=0

We calculate fractions


x+3x+8x+((4x+3)*2*2*9)/(2(2x+2)*2*2*9)+(-18x2/(2(2x+2)*2*2*9)+(-40x2/(2(2x+2)*2*2*9)-3-5=0



We calculate terms in parentheses: +((4x+3)*2*2*9)/(2(2x+2)*2*2*9), so:

(4x+3)*2*2*9)/(2(2x+2)*2*2*9

We multiply all the terms by the denominator


(4x+3)*2*2*9)

We get rid of parentheses

4x+3)*2*2*9

We add all the numbers together, and all the variables

4x

Back to the equation:

+(4x)



We can not solve this equation

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