-11=1/2(-6)+b

Solution for -11=1/2(-6)+b equation:

-11=1/2(-6)+b

We move all terms to the left:

-11-(1/2(-6)+b)=0


Domain of the equation: 2(-6)+b)!=0

b∈R


We multiply all the terms by the denominator


-(1-11*2(-6)+b)=0


We calculate terms in parentheses: -(1-11*2(-6)+b), so:

1-11*2(-6)+b

determiningTheFunctionDomain
b+1-11*2(-6)

We add all the numbers together, and all the variables

b+133

Back to the equation:

-(b+133)


We get rid of parentheses

-b-133=0

We add all the numbers together, and all the variables

-1b-133=0

We move all terms containing b to the left, all other terms to the right

-b=133

b=133/-1

b=-133