6(3x+4)-18=2(9x+3)

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Solution for 6(3x+4)-18=2(9x+3) equation: 



6(3x+4)-18=2(9x+3)

We move all terms to the left:

6(3x+4)-18-(2(9x+3))=0

We multiply parentheses

18x-(2(9x+3))+24-18=0



We calculate terms in parentheses: -(2(9x+3)), so:

2(9x+3)

We multiply parentheses

18x+6

Back to the equation:

-(18x+6)



We add all the numbers together, and all the variables

18x-(18x+6)+6=0

We get rid of parentheses

18x-18x-6+6=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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