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X+1/2X=-12
We move all terms to the left:
X+1/2X-(-12)=0
Domain of the equation: 2X!=0We add all the numbers together, and all the variables
X!=0/2
X!=0
X∈R
X+1/2X+12=0
We multiply all the terms by the denominator
X*2X+12*2X+1=0
Wy multiply elements
2X^2+24X+1=0
a = 2; b = 24; c = +1;
Δ = b2-4ac
Δ = 242-4·2·1
Δ = 568
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{568}=\sqrt{4*142}=\sqrt{4}*\sqrt{142}=2\sqrt{142}$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(24)-2\sqrt{142}}{2*2}=\frac{-24-2\sqrt{142}}{4} $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(24)+2\sqrt{142}}{2*2}=\frac{-24+2\sqrt{142}}{4} $
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