12(s+2)=2(s-11)-34

Solution for 12(s+2)=2(s-11)-34 equation:

12(s+2)=2(s-11)-34

We move all terms to the left:

12(s+2)-(2(s-11)-34)=0

We multiply parentheses

12s-(2(s-11)-34)+24=0


We calculate terms in parentheses: -(2(s-11)-34), so:

2(s-11)-34

We multiply parentheses

2s-22-34

We add all the numbers together, and all the variables

2s-56

Back to the equation:

-(2s-56)


We get rid of parentheses

12s-2s+56+24=0

We add all the numbers together, and all the variables

10s+80=0

We move all terms containing s to the left, all other terms to the right

10s=-80

s=-80/10

s=-8