3(6-x)+2(x-3)=5+2(3x+1)-x

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Solution for 3(6-x)+2(x-3)=5+2(3x+1)-x equation: 



3(6-x)+2(x-3)=5+2(3x+1)-x

We move all terms to the left:

3(6-x)+2(x-3)-(5+2(3x+1)-x)=0

We add all the numbers together, and all the variables

3(-1x+6)+2(x-3)-(5+2(3x+1)-x)=0

We multiply parentheses

-3x+2x-(5+2(3x+1)-x)+18-6=0



We calculate terms in parentheses: -(5+2(3x+1)-x), so:

5+2(3x+1)-x

determiningTheFunctionDomain
2(3x+1)-x+5

We add all the numbers together, and all the variables

-1x+2(3x+1)+5

We multiply parentheses

-1x+6x+2+5

We add all the numbers together, and all the variables

5x+7

Back to the equation:

-(5x+7)



We add all the numbers together, and all the variables

-1x-(5x+7)+12=0

We get rid of parentheses

-1x-5x-7+12=0

We add all the numbers together, and all the variables

-6x+5=0

We move all terms containing x to the left, all other terms to the right

-6x=-5

x=-5/-6

x=5/6

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