(6b-2)(3b)=b

Solution for (6b-2)(3b)=b equation:

(6b-2)(3b)=b

We move all terms to the left:

(6b-2)(3b)-(b)=0

We add all the numbers together, and all the variables

-1b+(6b-2)3b=0

We multiply parentheses

18b^2-1b-6b=0

We add all the numbers together, and all the variables

18b^2-7b=0

a = 18; b = -7; c = 0;
Δ = b2-4ac
Δ = -72-4·18·0
Δ = 49
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{49}=7$
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-7)-7}{2*18}=\frac{0}{36}
=0
$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-7)+7}{2*18}=\frac{14}{36}
=7/18
$