3-6(x-1)=9-2(1+3x)+2

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Solution for 3-6(x-1)=9-2(1+3x)+2 equation: 



3-6(x-1)=9-2(1+3x)+2

We move all terms to the left:

3-6(x-1)-(9-2(1+3x)+2)=0

We add all the numbers together, and all the variables

-6(x-1)-(9-2(3x+1)+2)+3=0

We multiply parentheses

-6x-(9-2(3x+1)+2)+6+3=0



We calculate terms in parentheses: -(9-2(3x+1)+2), so:

9-2(3x+1)+2

determiningTheFunctionDomain
-2(3x+1)+9+2

We add all the numbers together, and all the variables

-2(3x+1)+11

We multiply parentheses

-6x-2+11

We add all the numbers together, and all the variables

-6x+9

Back to the equation:

-(-6x+9)



We add all the numbers together, and all the variables

-6x-(-6x+9)+9=0

We get rid of parentheses

-6x+6x-9+9=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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