2(3a-7)-3(4a+2)=2-2(a+2)

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Solution for 2(3a-7)-3(4a+2)=2-2(a+2) equation: 



2(3a-7)-3(4a+2)=2-2(a+2)

We move all terms to the left:

2(3a-7)-3(4a+2)-(2-2(a+2))=0

We multiply parentheses

6a-12a-(2-2(a+2))-14-6=0



We calculate terms in parentheses: -(2-2(a+2)), so:

2-2(a+2)

determiningTheFunctionDomain
-2(a+2)+2

We multiply parentheses

-2a-4+2

We add all the numbers together, and all the variables

-2a-2

Back to the equation:

-(-2a-2)



We add all the numbers together, and all the variables

-6a-(-2a-2)-20=0

We get rid of parentheses

-6a+2a+2-20=0

We add all the numbers together, and all the variables

-4a-18=0

We move all terms containing a to the left, all other terms to the right

-4a=18

a=18/-4

a=-4+1/2

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